How to store a matrix, A, in variable X, where X is also carrying a counter "i"

1 vue (au cours des 30 derniers jours)
I have a matrix A, which I want to store in a varaible X.
Now I can do,
X=A;
But the varaible is X is having a counter i, beacuse the value of X variable in one iteration will be used in the next iteration and so on.
So, it put a counter like this;
X(i)=A;
But, in the above line, the indices error - Unable to perform assignment because the indices on the left side are not compatible with the size of the right side - is shown.
What should be the correct syntax, plaease tell me.

Réponse acceptée

Ulli Srinivasu
Ulli Srinivasu le 16 Sep 2020
Hi Neeraj,
simply create a structure.
X = struct();
X(i).A = A;
  3 commentaires
Ulli Srinivasu
Ulli Srinivasu le 16 Sep 2020
use x(j-1).A, x(j).A, x(j+1).A
Neeraj Kumar
Neeraj Kumar le 16 Sep 2020
It worked!! Thanks Ulii Srinivasu!!

Connectez-vous pour commenter.

Plus de réponses (1)

Sindar
Sindar le 16 Sep 2020
Simple way: add a third dimension, "pages":
X(:,:,i) = A;
But, if you only need the last iteration, it's better to store just the current and last iteration. Something like:
n=10;
m=4;
X_new = rand(n,m);
for ind=1:10
X_old = X_new;
X_new = X_old.^2;
end
  4 commentaires
Walter Roberson
Walter Roberson le 16 Sep 2020
What you are seeing displayed is not two matrices, it is a way to represent a multidimensional matrix of numeric values on the command window.
I would suggest that you use SIndar's X_old strategy.
Neeraj Kumar
Neeraj Kumar le 16 Sep 2020
Modifié(e) : Neeraj Kumar le 16 Sep 2020
Ok, i will try this X_old strategy. Thanks Walter! Thanks Sindar!

Connectez-vous pour commenter.

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Produits


Version

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by