How to same size of plot and histogram

5 vues (au cours des 30 derniers jours)
Mustafa Vural
Mustafa Vural le 21 Sep 2020
Commenté : Mustafa Vural le 21 Sep 2020
I want to compare my function with given parameters with my histogram with generated random numbers.
So, I want to put these two plots in one figure. But my histogram is on the y-axis much more bigger (around 250) than my fplot (around 2). How can I put them in the same size and compare them? I want to see if my histogram has the same shape as my function.
clear all;
clf
n=1000
t0 = 0.5;
T_A = 1;
b_A = 2;
fun_A2p = @(x) (b_A/T_A).*(x/T_A).^(b_A-1).*(exp(-(x/T_A).^(b_A)));
fun_A3p = @(x) (b_A/(T_A-t0)).*((x-t0)/(T_A-t0)).^(b_A-1).*(exp(-((x-t0)/(T_A-t0)).^(b_A)));
fplot(fun_A2p,[0,10], 'LineWidth',2, "Color", 'b')
hold on
fplot(fun_A3p,[0,10], 'LineWidth',2, "Color", 'r', 'LineStyle', '--')
hold on
for v_T = 1:length(T_A)
for v_b = 1:length(b_A)
data2p(:,v_b,v_T) = wblrnd(v_T,v_b, [n,1]);
data3p(:,v_b,v_T) = wblrnd(v_T,v_b, [n,1]) + t0;
end
end
h1= histogram(data2p);
hold on;
h2= histogram(data3p);
set(h1,'FaceColor',[0 0 1],'EdgeColor',[0 0 1],'facealpha',0.5);
set(h2,'FaceColor',[1 0 0],'EdgeColor',[1 0 0],'facealpha',0.5);
ax = gca;
ax.XLim=[0,5];
ax.YLim=[0,300];
grid on; %Gitter anzeigen
box on; %Rahmen zeigen
title ('Vergleich Dichtefunktion mit Histogram');
xlabel('Lebensdauer t');
ylabel('Dichtefunktion f(x)');
legend('2 parametrisch', '3 parametrisch')

Réponse acceptée

the cyclist
the cyclist le 21 Sep 2020
I think that using
h1= histogram(data2p,'Normalization','pdf');
h2= histogram(data3p,'Normalization','pdf');
and of course removing
ax.YLim=[0,300];
will get you much closer to what you want.
You could also just use the histcounts function to get the counts, and then the bar function to plot them (applying whatever normalization factor you want).
  1 commentaire
Mustafa Vural
Mustafa Vural le 21 Sep 2020
Thank you very much, it works pretty good! I appreciate it.

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