Rotate Spherical Coordinates to find new Vector Magnitude
16 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Dear Forum,
I am given a ,,. Does Matlab have a function to convert and find the from a new ?
6 commentaires
Ameer Hamza
le 29 Sep 2020
In case when r1=100, theta1=0, and phi1=0, and if by the negative value of r, you mean reversing the position vector, then in that case, you can say that r1=-100, theta1=180, and phi1=0 is equivalent to the first vector. But for any other value of theta and phi, you cannot get the same vector.
Réponse acceptée
Sindar
le 29 Sep 2020
It sounds like the goal is to find the projection of the vector along the direction defined by theta=100, phi=150. If this is the case, one way is:
[x2,y2,z2] = sph2cart(150*pi/180,100*pi/180,1);
[x1,y1,z1] = sph2cart(phi1*pi/180,theta1*pi/180,r1);
v12_proj = x1.*x2 + y1.*y2 + z1.*z2;
Plus de réponses (0)
Voir également
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!