for loop taking too long to operate

11 vues (au cours des 30 derniers jours)
SChow
SChow le 6 Oct 2020
Commenté : SChow le 6 Oct 2020
I have a matrices (b1 and popx) with size 25000x50000, code is a vector which contains unique values in b1 (of length 300). For elements in popx which correspond to each unique value of b1, I need the sum of popx,
The below code takes very long (>2 hours) to operate, Any help to lower computation time is much appreciated
for i=1:300
popx1=popx;
popx1(b1~=code(i))=NaN;
popn=nansum(nansum(popx1));
popn1(i)=popn;
end;

Réponse acceptée

Jos (10584)
Jos (10584) le 6 Oct 2020
Pre-allocation, and recoding using logical indexing and sum should speed things up
popn1 = nan(300,1) ; % pre-allocation
for i=1:300
tf = b1 == code(i) ;
popn1(i) = sum(popx(tf), 'all') ;
end;
  1 commentaire
SChow
SChow le 6 Oct 2020
much quicker , thanks

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by