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for loop taking too long to operate

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SChow
SChow on 6 Oct 2020
Commented: SChow on 6 Oct 2020
I have a matrices (b1 and popx) with size 25000x50000, code is a vector which contains unique values in b1 (of length 300). For elements in popx which correspond to each unique value of b1, I need the sum of popx,
The below code takes very long (>2 hours) to operate, Any help to lower computation time is much appreciated
for i=1:300
popx1=popx;
popx1(b1~=code(i))=NaN;
popn=nansum(nansum(popx1));
popn1(i)=popn;
end;

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Accepted Answer

Jos (10584)
Jos (10584) on 6 Oct 2020
Pre-allocation, and recoding using logical indexing and sum should speed things up
popn1 = nan(300,1) ; % pre-allocation
for i=1:300
tf = b1 == code(i) ;
popn1(i) = sum(popx(tf), 'all') ;
end;

  1 Comment

SChow
SChow on 6 Oct 2020
much quicker , thanks

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