How to create multiple matrices with different sizes without a loop?
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Say I have a matrix with M elements. In this case its 3.
A = [1 2 3];
And I want to create M vectors with N random numbers from the interval 0 to each of the element in A.
X = randi([0,A(1)], 1, N)
Y = randi([0,A(2)], 1, N)
Z = randi([0,A(3)], 1, N)
How can I do this without using loops? Is it possible?
0 commentaires
Réponse acceptée
James Tursa
le 7 Oct 2020
You will either need to use loops, or hide the loops behind a function call (e.g., arrayfun):
result = arrayfun(@(x)randi([0 x],1,N),A,'uni',false);
0 commentaires
Plus de réponses (1)
Walter Roberson
le 7 Oct 2020
N = 100;
A = [1 2 3];
M = length(A);
XYZcell = num2cell(floor(rand(M, N) .* (A(:)+1)), 2);
[X, Y, Z] = XYZcell{:};
counts = accumarray(Z(:)+1, 1);
bar(0:3, counts)
1 commentaire
Walter Roberson
le 7 Oct 2020
Note: this method is very slightly biased against 0 -- but not enough that you would notice.
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!