Not able to extract data from fig file having subplots

There are 7 subplots in my fig file , am able to extract data from all but not able to extract data from 6 fig .
Could anyone tell me why the 6th subplot data am not able to extract am using this code.Once i execute the command
the data gets vanished from the figure file
clc
clear all
h=findobj(subplot(7,1,6),'Type','line');
x=get(h,'Xdata');
y=get(h,'Ydata');
for i =1:size(y)
z{i,1}=(y{i,1}');
end

8 commentaires

Does axes 6 also contain a line object? Maybe it contains some other graphics object.
Yes ,it looks like line object only,whenever am executing the command for sixth subplot the h value is 0x0 graphics placeholder
h = 0x0 means that it is not a line. Can you share your .fig file.
sorry,i cant share the fig file ,can you please tell me other options which i can try
Check what type of graphic object is present. What is the output of these lines
ax = subplot(7,1,6);
ax.Children
Sandeep Nair
Sandeep Nair le 8 Oct 2020
Modifié(e) : Sandeep Nair le 8 Oct 2020
When i open the file i can see the figure with data on it .
When i ran the command
get(subplot(7,1,6),'Type')
it returned
'axes'
when i open the file i can see the data and i can see the datatips as well ,but when am running command for findobj
the graph is disappearing.Please help
Without knowing what is present in subplot 6, it is difficult to suggest a solution. The children property tells what type of object is children of that axes.
VBBV
VBBV le 11 Oct 2020
Modifié(e) : VBBV le 11 Oct 2020
clc
clear all
ax = subplot(7,1,6)
h=findobj(ax,'Type','line');
x=get(h,'Xdata');
y=get(h,'Ydata');
for i =1:size(y)
z{i,1}=(y{i,1}');
end
use the property, value type arguments for findobj . pass the handle of subplot to findobj

Connectez-vous pour commenter.

Réponses (0)

Catégories

En savoir plus sur Creating, Deleting, and Querying Graphics Objects dans Centre d'aide et File Exchange

Tags

Modifié(e) :

le 11 Oct 2020

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by