read csv file and convert 'double' to binary

f = csvread('S21.csv',double=>binary);

I read .csv file in 'double'

ex) f(1,1) = 1.5111

I want to convert it to binary, 010101010,

no data loss as possible as.

How can I do???

Thank you for your coperation

Answer 1

[Ameer Hamza]

See dec2hex(): https://www.mathworks.com/help/matlab/ref/dec2hex.html or num2hex(): https://www.mathworks.com/help/matlab/ref/num2hex.html if you want to use IEEE-754 format for conversion.

[je heo]

thank you for your answer

but i want only binary form which has '0100010101' .

[Walter Roberson]

The example you posted first had 9 bits, and this version has 10 bits. How many bits of output are you looking for?

reshape(dec2bin(typecast(1.5111, 'uint8'),8).', 1, [])

ans = '0000010111000101100011110011000101110111001011011111100000111111'

[je heo]

thank you for your answer.. ^^

[Walter Roberson]

Note that the above is just one representation of 1.5111, and that it is not to be interpreted as something like

00000101.11000101100011110011000101110111001011011111100000111111

You get closer to that kind of representation with

reshape(dec2bin(typecast(swapbytes(1.5111), 'uint8'),8).', 1, [])

ans = '0011111111111000001011010111011100110001100011111100010100000101'

but this again is not to be interpreted as a binary fraction, at least not without careful examination.

The first bit is the sign bit. The next 11 bits are the exponent, with a bias of 1022. The remaining 52 bits are a binary fraction with an implied "1." in front of it.