Unable to Plot from Excel
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Avinav Kumar
le 12 Oct 2020
Commenté : Walter Roberson
le 12 Oct 2020
I am unable to plot from Excel Sheet. My code is s follows. If someone can please help
function pushbutton1_Callback(hObject, eventdata, handles)
% hObject handle to pushbutton1 (see GCBO)
% eventdata reserved - to be defined in a future version of MATLAB
% handles structure with handles and user data (see GUIDATA)
[file, path] = uigetfile('*.xls');
handles.fileName = fullfile(file, path);
guidata(hObject,handles);
% --- Executes on button press in pushbutton2.
function pushbutton2_Callback(hObject, eventdata, handles)
% hObject handle to pushbutton2 (see GCBO)
% eventdata reserved - to be defined in a future version of MATLAB
% handles structure with handles and user data (see GUIDATA)
if isfield(handles, 'fileName')
filename = get(handles.fileName);
values = xlsread(filename);
xCol = values(:,2);
yCol = values(:,3);
set(handles.axes1,'Visible','on');
plot(handles.axes1,xCol,yCol)
end
3 commentaires
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Walter Roberson
le 12 Oct 2020
handles.fileName = fullfile(file, path);
That creates fileName as a character vector field inside handles.
filename = get(handles.fileName);
If handles.FileName were a handle, then that would return a structure of public properties of the handle.
However, handles.FileName is not a handle, just a character vector. You just need
filename = handles.fileName;
2 commentaires
Walter Roberson
le 12 Oct 2020
[file, path] = uigetfile('*.xls');
handles.fileName = fullfile(file, path);
The first output from uigetfile is the file name, and the second output is the directory.
The first input to fullfile should be the directory and the second input is the file name.
You are passing in the file name first and then the directory name, so you are going to be constructing a file name such as h93_b3.xlsx\Users\Aninav\Desktop\MATLAB\project7 when you wanted \Users\Aninav\Desktop\MATLAB\project7\h93_b3.xlsx
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