Annually averaging of a 4D matrix

3 vues (au cours des 30 derniers jours)
HA
HA le 12 Oct 2020
Commenté : HA le 14 Oct 2020
Hello,
I have a 4D data set (e.g. lon : lat : height : month) that I need to annually average. Usually with a 3D data set (e.g. lon : lat : month) I would use-
s=size(A);
B = squeeze(nanmean(reshape(A,[s(1:2),12,s(3)/12]),3));
For a 4D data set I have tried-
s=size(A);
B = squeeze(nanmean(reshape(A,[s(1:2:3),12,s(4)/12]),4));
I am guessing that I need to put something else in the square bracket or I am changing something wrong, but after trying various alterations I have decdied to ask the community.
Thank you.

Réponse acceptée

Rik
Rik le 12 Oct 2020
You are using the color operator incorrectly. 1:2:3 doesn't mean [1 2 3], but [1 3].
If your syntax does indeed work for you, the edit below should be what you're looking for.
s=size(A);
B = squeeze(nanmean(reshape(A,[s(1:3),12,s(4)/12]),4));
  1 commentaire
HA
HA le 14 Oct 2020
Aha, of course it does! Thank you, I can see how that is a silly mistake now!

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by