convert to double equation
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
my function gives an error while converting to double a one place (marked as %****) while at other places it works fine.
syms Y4(x)
syms Y1(x)
syms Y2(x)
syms Y5(x)
syms Y7(x)
syms Y3(x)
syms Y6(x)
sym =x
syms a
syms b
v=input('velocity ');
cl=input('Cl ');
%to plot elliptical lift distribution
w=input('total weight ');
ws=input('half wing span ');
disp(ws);
b1=double(9.81*(4*(w/2))/(2*pi*ws));
disp(b1);
Y7(x)=(b1/(ws))*((ws^2-x^2))^0.5;
disp(Y7(x));
n=input('no of sections ');
k=input('no. of tapered section');
for i=1:n
m=0;
c=0;
cr=input('Root cord for that section ');
ct=input('tip cord for that section ');
l1=input('length of that section ' );
L1=double((1.225*cl*(v^2)*cr)/2); %lift distribution per unit span
L2=double((1.225*cl*(v^2)*ct)/2);
disp(L1);
disp(L2);
if cr==ct
m=0;
c=L1;
if i==1 && k==1;
Y1(x)=-(m/2)*x+(c/2); %linear lift eqn untapered section
else n==3 && i==2;
Y2(x)=-(m/2)*x+(c/2); %linear lift eqn untapered section
end
else
if k==2
m=double((L1-L2)/l1);
c=L1;
Y1(x)=-(m/2)*x+(c/2); %linear lift eqn tapered section
else
l2=input('starting point of the taper section ');
m=double((L1-L2)/l1);
disp(m);
c=L1+m*l2;
disp(c);
Y3(x)=-(m/2)*x+(c/2); %linear lift eqn tapered section
end
end
end
Y4(x)=Y1(x)+Y7(x); % schrenk eqn untapered section
Y5(x)=Y2(x)+Y7(x); %schrenk eqn untapered section
Y6(x)=Y3(x)+Y7(x); % schrenk eqn tapered section
%VIT schrenk eqn
% Y1=-0*x+33.037;
% Y2=-27.10*x+37.02;
% Y4(x)=(-0*x+33.037/2 +(110.825*(0.1296-x^2)^0.5)/2);
% Y5(x)=((-27.10/2)*x+37.02/2 +(110.825*(0.1296-x^2)^0.5)/2);
xv=0;
I=[];
W1=input('length of first section ');
if n==3
W2=input('length of 2nd section ');
end
if n==3
while xv(end)<= (ws+0.01) % to plot shear force with 3 sections
if xv(end) <=W1
I(end+1)=double(int(Y4,x,0,xv(end)));
elseif xv(end)>=W1 && xv(end)<=W2
I(end+1)=double(int(Y5,x,0,xv(end)));
else
I(end+1)=double(int(Y6,x,0,xv(end))); %****
end
xv(end+1)=xv(end)+0.01;
end
else
while xv(end)<= (ws+0.01) % to plot shear force with 2 sections
if xv(end) <=W1
I(end+1)=double(int(Y4,x,0,xv(end)));
else
I(end+1)=double(int(Y6,x,0,xv(end)));
end
xv(end+1)=xv(end)+0.01;
end
end
xv(end)=[];
xy=0;
a=0;
I2=int(Y4,a,x)
I4=int(Y5,a,x)
I5=int(Y6,a,x)
I3=[];
if n==3
while xy(end)<=(ws+0.01) % to plot BM with 3 sections
if xy(end)<=W1
I3(end+1)=double(int(I2,x,0,xy(end)));
elseif xy(end)>=W1 && xy(end)<=W2
I3(end+1)=double(int(I4,x,0,xy(end)));
else
I3(end+1)=double(int(I5,x,0,xy(end)));
end
xy(end+1)=xy(end)+0.01;
end
else
while xy(end)<=(ws+0.01) % to plot BM witH 2 section
if xy(end)<=W1
I3(end+1)=double(int(I2,x,0,xy(end)));
else
I3(end+1)=double(int(I5,x,0,xy(end)));
end
xy(end+1)=xy(end)+0.01;
end
end
xy(end)=[];
plot(xy,I3);grid %BM graph
% plot(xv,I);grid %shear force graph
1 commentaire
Réponses (0)
Voir également
Catégories
En savoir plus sur Calculus dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!