w= 1 0 1
w= 0 1 1
w= 0 1 0
how came this can be written in straight line
w= 1 0 1 0 1 1 0 1 0

 Réponse acceptée

Walter Roberson
Walter Roberson le 24 Avr 2011

0 votes

You might find this easier to understand:
w = []; for i = 1:30 w = [w, A(i), B(i), C(i)]; end

2 commentaires

Oleg Komarov
Oleg Komarov le 24 Avr 2011
Seriously :)?
Walter Roberson
Walter Roberson le 24 Avr 2011
Yup. Get it working first, and *then* optimize it.

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Plus de réponses (1)

Walter Roberson
Walter Roberson le 24 Avr 2011

0 votes

It cannot. The first one assigns the row vector [0 1 0] to w, but the second one assigns a row vector of length 9 to w.
If your original data is a 3 x 3 matrix instead, then
w = reshape(w.',1,numel(w));

7 commentaires

mahaveer hanuman
mahaveer hanuman le 24 Avr 2011
not working
mahaveer hanuman
mahaveer hanuman le 24 Avr 2011
those 'w' are vectors
Walter Roberson
Walter Roberson le 24 Avr 2011
What *exactly* do you have for input? And what *exactly* do you want for output?
w = 1 0 1
is not valid MATLAB input.
mahaveer hanuman
mahaveer hanuman le 24 Avr 2011
for i=1:30;
w=([A(i),B(i),Q(i)]);
end
after perfoming this
i got out put as
w=
1 0 1
w=
0 0 1
w=
1 1 1
and so on.........................
now i need to make them into one single bit stream
like
w=1 0 1 0 0 1 1 1 1 .....................
Oleg Komarov
Oleg Komarov le 24 Avr 2011
Preallocate before the loop:
w = zeros(1,30*3);
for ...
w(i*3-2:i*3) = ([A(i),B(i),Q(i)]);
end
Walter Roberson
Walter Roberson le 24 Avr 2011
N = 30;
w = reshape([reshape(A(1:N),1,N); reshape(B(1:N),1,N); reshape(C(1:N),1,N)], 1, 3*N);
The above does not assume that A, B, or C are row vectors or column vectors. If the shapes are known and consistent, the code can be simplified -- especially if you are putting together _all_ of the vector instead of just a subset of it.
For example, if they are all row vectors and you are using all of them, then
w = [A;B;C]; w = w(:).';
mahaveer hanuman
mahaveer hanuman le 24 Avr 2011
thanks its working

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