How can I divide an image into two halves? Then, after dividing it make each half independent, say
A = top half and
B = the bottom half.
So that I can extract features from each half.

2 commentaires

Nourou
Nourou le 8 Août 2014
Modifié(e) : Image Analyst le 8 Août 2014
Hi Jack, Azzi,
Please I need a clarification about the usage of the following method:
im=imread('yourimage')
n=fix(size(im,1)/2)
A=im(1:n,:,:);
B=im(n+1:end,:,:)
imshow(A)
figure
imshow(B)
I try to use it on a grayscale image, but the results are 2 blank images. Please how can I edit your code to make it divide my image. I know you use it with a rgb image.
Thank you!
Image Analyst
Image Analyst le 8 Août 2014
Modifié(e) : Image Analyst le 8 Août 2014
A and B are probably double for some reason. Try
imshow(A, []);
imshow(B, []);
Start your own question if you need more help.

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 Réponse acceptée

Azzi Abdelmalek
Azzi Abdelmalek le 2 Fév 2013
im=imread('yourimage')
n=fix(size(im,1)/2)
A=im(1:n,:,:);
B=im(n+1:end,:,:)
imshow(A)
figure
imshow(B)

10 commentaires

Jack Sparrow
Jack Sparrow le 2 Fév 2013
Thank you Azzi. .Is it also thesame procedure for more than two blocks?
Azzi Abdelmalek
Azzi Abdelmalek le 2 Fév 2013
I guess it's the same, unless there are tools for that in image processing toolbox.
Jack Sparrow
Jack Sparrow le 2 Fév 2013
okay thanks
Image Analyst
Image Analyst le 2 Fév 2013
There are tool in the Image Processing Toolbox. imcrop(). But Azzi, your method is simpler. imcrop() unfortunately it doesn't have an option (yet) where you can just pass in starting and ending rows and columns. It's based off a "rectangle" where you have to pass in [x, y, width, height] so you have to calculate width and height. It's a pain and I'm constantly telling the image processing team that we need a pixel-based option.
Jack Sparrow
Jack Sparrow le 2 Fév 2013
Thanks image analyst. Although I have already used the solution provided by Azzi
Explorer
Explorer le 31 Déc 2013
Modifié(e) : Azzi Abdelmalek le 31 Déc 2013
Please do necessary changes in below mentioned code for splitting image as left half and right half.
im=imread('yourimage')
n=fix(size(im,1)/2)
A=im(1:n,:,:);
B=im(n+1:end,:,:)
imshow(A)
figure
imshow(B)
% Read in image and display it.
rgbImage=imread('peppers.png');
subplot(2, 2, 1);
imshow(rgbImage);
% Get sizes of the images.
[rows, columns, numberOfColorChannels] = size(rgbImage);
middleColumn = int32(columns/2)
title('Right Half', 'FontSize', 25);
% Split them up.
leftHalf = rgbImage(:, 1:middleColumn, :);
rightHalf=rgbImage(:, middleColumn+1:end, :);
% Display them.
subplot(2, 2, 3);
imshow(leftHalf);
title('Left Half', 'FontSize', 25);
subplot(2, 2, 4);
imshow(rightHalf);
title('Right Half', 'FontSize', 25);
% Enlarge figure to full screen.
set(gcf, 'Units', 'Normalized', 'OuterPosition', [0 0 1 1]);
% Give a name to the title bar.
set(gcf, 'Name', 'Demo by ImageAnalyst', 'NumberTitle', 'Off')
Explorer
Explorer le 1 Jan 2014
Thank you Image Analyst.
zohreh nezami
zohreh nezami le 22 Juin 2017
thank you
suma g
suma g le 2 Avr 2018
sir u have given for left half and right half of the image... very helpful.i want to segment the face image into upper and bottom half of the face ... upper- forehead,eyes and eyebrows & lower- nose lips and chin CAN U GIVE ME SOME IDEA

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Plus de réponses (1)

utkarsh kumar
utkarsh kumar le 26 Avr 2019

0 votes

hi i am having a doubt in understanding the code.....in the below code
im=imread('yourimage')
n=fix(size(im,1)/2)
A=im(1:n,:,:);
B=im(n+1:end,:,:)
imshow(A)
figure
imshow(B)
What is the meaning of the highlighted one .
Thanks

1 commentaire

Image Analyst
Image Analyst le 26 Avr 2019
It says A is equal to rows 1 through n, all columns, all color rows. The colon means "all" if it's by itself, or "to" if it's in an expressions like 1:n.
So if n is the middle row, A will be the top half. Then B picks up from one row below the middle row. It says B equals all rows from one row below the middle row to the last row, and all columns and all color channels. If it's grayscale, having an extra : in there for the third index will not hurt - it will just ignore it.

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