hi... how do i generate 2, 6, 5, 3, vectors? in that order

2 commentaires

Walter Roberson
Walter Roberson le 21 Oct 2020
Do you mean that you need to run a calculation that gives you that vector as a result? If so then typically those assignments restrict the operations that are permitted?
KSSV
KSSV le 21 Oct 2020
A = [2 6 5 3] ;

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Ameer Hamza
Ameer Hamza le 21 Oct 2020

0 votes

A slightly unusual way, but it fulfills the requirement
fun = @(x) round(sin(-0.688014*x + 3.625700) .* exp(-0.367642*x) .* log(2609741*x));
y = fun(1:4)
Result
>> y
y =
2 6 5 3

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