Error using table2array -- Input argument must be a table.

15 vues (au cours des 30 derniers jours)
Jemuel Jeroham B
Jemuel Jeroham B le 21 Oct 2020
Modifié(e) : Adam Danz le 23 Oct 2020
When I run the below code, I get the error "Error using table2array (line 34)
Input argument must be a table."
app.store = table2array(app.UITable.Data);
  2 commentaires
Jemuel Jeroham B
Jemuel Jeroham B le 21 Oct 2020
app.UITable.Data -- is a table.
Bruno Luong
Bruno Luong le 21 Oct 2020
Type
dbstop if error
in command line. Run your app, when the error occurs, type
class(app.UITable.Data)
and see what returns

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Réponses (1)

Adam Danz
Adam Danz le 21 Oct 2020
Modifié(e) : Adam Danz le 23 Oct 2020
I don't see a question.
Apparently app.UITable.Data isn't a table. This can happen when the data are from the same class. In that case, you don't need table2array(). For example,
uif = uifigure();
uit = uitable(uif,'Data',magic(9)); % all numeric
>> uit.Data
ans =
47 58 69 80 1 12 23 34 45
57 68 79 9 11 22 33 44 46
67 78 8 10 21 32 43 54 56
77 7 18 20 31 42 53 55 66
6 17 19 30 41 52 63 65 76
16 27 29 40 51 62 64 75 5
26 28 39 50 61 72 74 4 15
36 38 49 60 71 73 3 14 25
37 48 59 70 81 2 13 24 35
uit2 = uitable(uif,'Data',string(magic(9))); % all strings
>> uit2.Data
ans =
9×9 string array
"47" "58" "69" "80" "1" "12" "23" "34" "45"
"57" "68" "79" "9" "11" "22" "33" "44" "46"
"67" "78" "8" "10" "21" "32" "43" "54" "56"
"77" "7" "18" "20" "31" "42" "53" "55" "66"
"6" "17" "19" "30" "41" "52" "63" "65" "76"
"16" "27" "29" "40" "51" "62" "64" "75" "5"
"26" "28" "39" "50" "61" "72" "74" "4" "15"
"36" "38" "49" "60" "71" "73" "3" "14" "25"
"37" "48" "59" "70" "81" "2" "13" "24" "35"

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