Can I use the PDEPE solver to solve the following dimensionless Transient PFR PDE? If not, what method do you reconmend?

1 vue (au cours des 30 derniers jours)
How do I expresss the last term of the PDE in the code?

Réponses (1)

David Goodmanson
David Goodmanson le 22 Oct 2020
Hello Rogelio,
For psi(t,eta) I assume that the boundary conditions are
psi(0,eta) = 0 for all eta
and
d psi(t,eta) / deta | = 0 for all t
| eta = 0
and a solution is intended for t >= 0. In that case a solution that fits the bc's is
psi(t,eta) = 1 -exp(-t/lambda)
i.e. no eta dependence at all.
  2 commentaires
Roger Vegeta
Roger Vegeta le 22 Oct 2020
psi(0,eta) = 0 ; for all eta.
d(psi)/d(eta) = 0 ; for eta = 0 for all time.
David Goodmanson
David Goodmanson le 22 Oct 2020
Modifié(e) : David Goodmanson le 23 Oct 2020
yes. so the solution from my previous comment works.

Connectez-vous pour commenter.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by