Sum modified laplacian operator

9 vues (au cours des 30 derniers jours)
Psk
Psk le 22 Oct 2020
Commenté : KSSV le 22 Oct 2020
ML(p, q) =| 2I(p, q) − I(p − 1, q) − I(p + 1, q) | + | 2I(p, q) − I(p, q − 1) − I(p, q + 1) | (2.2.6) where, I(p,q) denotes the pixel value located at the position (p,q).
My Image I is of size 256x256. To implement the above line, I am getting a zero index error as I have choosen p=1:256 and q=1:256. How to avoid getting a zero index error?

Réponses (1)

KSSV
KSSV le 22 Oct 2020
Modifié(e) : KSSV le 22 Oct 2020
for p = 2:255
for q = 2:255
% do what you want
end
end
  4 commentaires
Psk
Psk le 22 Oct 2020
But in that case that will be a deviation from the original formula. That is if i don't use (p-1) and q-1 for first and last index.
KSSV
KSSV le 22 Oct 2020
Then you resize your image into 258*258..

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