Given a matrix A replace elements not equal 0 and not equal 1 by 5. Use disp() function to print out the resulting array.
So far I've got
A(A~=0) = 5;
disp(A);
but do not know how to make it 0 AND 1.

2 commentaires

KSSV
KSSV le 27 Oct 2020
When you use ~=0 and replace those with 5, the elements whch have 1 also will be eplaced by 5 right?
Liam Bouchereau
Liam Bouchereau le 27 Oct 2020
Yeah so all elements that don't = 1 or 0 need to be replaced by the element 5

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 Réponse acceptée

Sudhakar Shinde
Sudhakar Shinde le 27 Oct 2020
Modifié(e) : Sudhakar Shinde le 27 Oct 2020
Try this:
A((A>1)|(A<0))=5

5 commentaires

Sudhakar Shinde
Sudhakar Shinde le 27 Oct 2020
But here is a question why you would like to do this operation? At the last you know all the elements will be '5' in result if need to use both the conditions.
Liam Bouchereau
Liam Bouchereau le 27 Oct 2020
Oh no, so I want to replace all elements that don't equal 1 or 0. So the array should be made up of 0's 1's and 5's like so...
A = [-1 0 4 6; 1 1 0 2; -7 0 5 0; 5 1 5 1];
would become
A = [5 0 5 5 1 1 0 5 5 0 5 0 5 1 5 1]
Then you can simply use:
A((A>1)|(A<0))=5
Liam Bouchereau
Liam Bouchereau le 27 Oct 2020
Thankyou
Sudhakar Shinde
Sudhakar Shinde le 27 Oct 2020
Welcome

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Plus de réponses (1)

Stephen23
Stephen23 le 27 Oct 2020
Modifié(e) : Stephen23 le 27 Oct 2020
Use AND instead of OR:
>> A = [-1,0,4,6;1,1,0,2;-7,0,5,0;5,1,5,1]
A =
-1 0 4 6
1 1 0 2
-7 0 5 0
5 1 5 1
>> A(A~=0&A~=1) = 5
A =
5 0 5 5
1 1 0 5
5 0 5 0
5 1 5 1

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