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How to convert a vector of integers to a vector of characters?

9 vues (au cours des 30 derniers jours)
Michael
Michael le 9 Fév 2013
Hi - I have a vector of ints, typically 0/1, like this:
[0 0 0 0 1 0 0 0 0 1]
and I want to get this:
['0' '0' '0' '0' '1' '0' '0' '0' '0' '1']
But I cannot figure it out for the life of me. I'm sure it's simple. Thanks for your time and help.

Réponse acceptée

James Tursa
James Tursa le 10 Fév 2013
Another method for single digits:
A = [0 0 0 0 1 0 0 0 0 1];
B = char(A+'0');

Plus de réponses (3)

Wayne King
Wayne King le 9 Fév 2013
Modifié(e) : Wayne King le 9 Fév 2013
A = [0 0 0 0 1 0 0 0 0 1];
B = num2str(A);
Now B is a vector of characters
  2 commentaires
Michael
Michael le 9 Fév 2013
Hi Wayne -- I knew of num2str and tried that, but it turns out you're right. But what I figured out was that it was the extra spaces in the result of num2str that was throwing me off. i.e. num2str([0 0 0 0 0]) = '0 0 0 0 0', which is length 9 or something (but not 5). I removed the spaces from the result of num2str and it worked great. Thanks for the help.
Wayne King
Wayne King le 9 Fév 2013
glad it helped

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Azzi Abdelmalek
Azzi Abdelmalek le 9 Fév 2013
Modifié(e) : Azzi Abdelmalek le 9 Fév 2013
a = [0 0 0 0 1 0 0 0 0 1];
y=arrayfun(@(x) cellstr(num2str(x)),a)
% To get any character
y{4} % for e.g

Jan
Jan le 10 Fév 2013
Modifié(e) : Jan le 10 Fév 2013
Instead of removing the spaces from the output of num2str, you can create string without spaces directly:
a = [0 0 0 0 1 0 0 0 0 1];
s = sprintf('%d', a);
Another fast but more strange method is:
s = char('0' + a);

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