How to fix it.
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Nisar Ahmed
le 28 Oct 2020
Commenté : Nisar Ahmed
le 28 Oct 2020
wav dimentions are
wav = 5001*1
and I want to change it as wav = 5001*5
How I can reshape it?
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Steven Lord
le 28 Oct 2020
So you want to take 5001 values and generate 25005 (5001 times 5) values using those values. How do you want to generate the additional 20004 values?
Make duplicate copies?
x = (1:6).'
y = repmat(x, 1, 5)
Offset the copies by a certain amount? This approach uses implicit expansion; if you're using an older release you could use bsxfun.
x = (1:6).'
y = x + (0:10:40)
Pad with 0 values or with random data?
x = (1:6).'
y = [x, zeros(size(x, 1), 5)]
z = [x, rand(size(x, 1), 5)]
w = [x, randi([7 11], size(x, 1), 5)]
Something else? If so, please explain in detail how you want to generate the additional values.
3 commentaires
Elijah McNeil
le 28 Oct 2020
His code does that, Just write this.
x = (1:5000).';
wav = repmat(x, 1, 5).
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Elijah McNeil
le 28 Oct 2020
Modifié(e) : Elijah McNeil
le 28 Oct 2020
This should work
wav = 5001*1
wav = wav*5
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