# How to fix it.

3 views (last 30 days)
Nisar Ahmed on 28 Oct 2020
Commented: Nisar Ahmed on 28 Oct 2020
wav dimentions are
wav = 5001*1
and I want to change it as wav = 5001*5
How I can reshape it?

Steven Lord on 28 Oct 2020
So you want to take 5001 values and generate 25005 (5001 times 5) values using those values. How do you want to generate the additional 20004 values?
Make duplicate copies?
x = (1:6).'
y = repmat(x, 1, 5)
Offset the copies by a certain amount? This approach uses implicit expansion; if you're using an older release you could use bsxfun.
x = (1:6).'
y = x + (0:10:40)
Pad with 0 values or with random data?
x = (1:6).'
y = [x, zeros(size(x, 1), 5)]
z = [x, rand(size(x, 1), 5)]
w = [x, randi([7 11], size(x, 1), 5)]
Something else? If so, please explain in detail how you want to generate the additional values.

Nisar Ahmed on 28 Oct 2020
I want to generate duplicate values (5000) in five columns rather than one...
Elijah McNeil on 28 Oct 2020
His code does that, Just write this.
x = (1:5000).';
wav = repmat(x, 1, 5).
Nisar Ahmed on 28 Oct 2020
Elijah McNeil, thanks dear, Now it is working

Elijah McNeil on 28 Oct 2020
Edited: Elijah McNeil on 28 Oct 2020
This should work
wav = 5001*1
wav = wav*5

Nisar Ahmed on 28 Oct 2020
It is not working, perhaps I'm unable to explain my point...
the size of wav is 5000 1 and I want reshap it as 5000 5
Elijah McNeil on 28 Oct 2020
Wait 5000 rows and 1 column?
Nisar Ahmed on 28 Oct 2020
5000 rows and 5 columns, each column is duplicate of other.