If statement for identifying row/column vectors/matrix/scalars

The question I am trying to solve, is how to create a function that recognizes the input given as either a colum vector, row vector, matrix, or scalar, depending on which category the input falls under it will execute simple arithmetic, that I can do. I have to create a function, myvec(x) that

the simple arithmetic I can execute, however, Im not sure how to type the if statements for the conditions the question prompts, for example, for the first condition how would I type

function y=myvec(x)

if y=rowvec? [1:n]? [1,n]?

or what is the correct way to do this, thank you

Answer 1

[Sudhakar Shinde]

'isrow' function returns true if input is row vector.

 isrow(in)

'iscolumn' function returns true if input is column vector.

 iscolumn(in)

'ismatrix' function returns true if input is matrix.

 ismatrix(in)

'isscalar' function returns true if input is scalar.

isscalar(in)

[Sudhakar Shinde]

example below

function y=myvec(x)
if isrow(x)  %Check if row vector
    ReveresRow = sort(x,'descend'); %Reverse elements
    y = ReveresRow.^2;  %Square
end
end

you can add else if conditions for column vector, matrix or scalar

[Joseph DeMaria]

Awesome this is helping so much! Appreciate your guys help so much, so far for my functions code I have

function y=myvec(x)

if isrow(x)

flip(x)

y=x.^2

if iscolumn(x)

y=vec-.5

if ismatrix(x)

y=(x*(x')).^2

if isscalar(x)

y=x

end

end

end

end

end

is this right for such conditions the question prompts?