looking up entire matrix for if then loop

Given A=[1 2 3 4 5 ]

• I want to see when A > 1 and count how many times that was true (output should be 4 times)
• I want to see when A > 2 and count how many times that was true (output should be 3 times)
• I want to see when A > 3 and count how many times that was true (output should be 2 times)
• I want to see when A > 4 and count how many times that was true (output should be 1 time)
• I want to see when A > 5 and count how many times that was true (output should be 0 time)

I tried using below approach, but it does not output what I intended. I think it is only looking at one cell at a time.

is there a way to look entire matrix and get the count?

clear
n=5; 
count=0;
r=exprnd(5,1,n);
for x=1:n
if r > x
count=count+1;
a(x)=count; %record output
else
count=count;
a(x)=count; %record output
end
end

Answer 1

[Ameer Hamza]

Here is a loop-free simpler way

n=5; 
count=0;
r=exprnd(5,1,n);

a = sum(r(:) > (1:n))

Result

>> r
r =
    1.3006   15.7725    4.8618    1.7525    1.5769
>> a
a =
     5     2     2     2     1

[Daniel Lee]

wowwwww never even knew that was possible... thanks bunch

[Ameer Hamza]

Yes, a very powerful aspect of MATLAB is vectorization, which makes the implementation of mathematical operations much simpler.

I am glad to be of help!

Answer 2

[Mathieu NOE]

hello

why not simply do that (example for when A > 1 and count how many times that was true (output should be 4 times)

A=[1 2 3 4 5 ];
k = find(A>1);
count = length(k);

[Daniel Lee]

Mathieu, thanks for the response as well-- I didnt know about find command. Will use it next time!