How to cut out/delete rows in a cell

2 vues (au cours des 30 derniers jours)
Simon Preuss
Simon Preuss le 5 Nov 2020
Commenté : Simon Preuss le 5 Nov 2020
Hello,
i want to cut out the first 100 rows in the cell and dont know how. I tried the following code, but that just starts at the 127th value
for u = 1:5
for i = 1:5
mu_short_Mess_20kmh_HA{u,i} = mu_20kmh_all_VA{u,i}(126:end);
mu_mean_cell_Mess_20kmh_HA{u,i} = mean(mu_short_Mess_20kmh_HA{u,i});
end
end
If it doesn't work as simple as i think it could I'm looking forward for any suggestions.

Réponse acceptée

VBBV
VBBV le 5 Nov 2020
% if true
% code
%end
for u = 1:5
for i = 1:5
mu_short_Mess_20kmh_HA{u,i} = mu_20kmh_all_VA{u,i}(101:end,:);
mu_mean_cell_Mess_20kmh_HA{u,i} = mean(mu_short_Mess_20kmh_HA{u,i});
end
end
  1 commentaire
Simon Preuss
Simon Preuss le 5 Nov 2020
Thanks, thats what i was looking for.

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Plus de réponses (2)

Monika Jaskolka
Monika Jaskolka le 5 Nov 2020
Modifié(e) : Monika Jaskolka le 5 Nov 2020
It removes up to the 127th element because that's what the code says to do where it has (126:end).
If you want to remove the first 100 rows, you should do the following:
mu_short_Mess_20kmh_HA{u,i} = mu_20kmh_alle_VA{u,i}(101:end,:);
For more information about accessing elements in a matrix, see the Array Indexing page.

dpb
dpb le 5 Nov 2020
mu_mean_Mess_20kmh_HA=cellfun(@(c) mean(c(126:end,:)),mu_20kmh_all_VA);
Don't need explicit loop; you just forgot the column colon subscript to pull all the columns for the wanted rows.

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