Function inside for loop not working

8 views (last 30 days)
Hi,
I am trying to iterate the diagonal filling of a previously defined, 0 valued hypercube object with a for loop of the following form:
EDIT - REMAINING CODE:
% Load and adjust test image, convert to .png (probably unnecessary)
addpath('D:\Users\Peter\Desktop\Masterarbeit\Messdaten\Bilder_Einfach');
img = imread('BspBild_1.jpg');
imwrite(img, 'BspBild.png');
img = double(rgb2gray(imread('BspBild.png')));
img = rescale(img);
sz = size(img);
% Create empty hypercube
zerocube = zeros(detformat_y, 2*detformat_x, n_lambda);
hcube = hypercube(zerocube, wavelengths);
% Add image to the first band
hcube = assignData(hcube, 1:411, detformat_x/2+1:640+detformat_x/2, 1, img);
% Show image as first hypercube band (for testing reasons)
figure(2)
imshow(hcube.DataCube(:, :, 1))
title('Cube-Ausschnitt')
% loop to "shear" image in the wavelength direction EDIT - END
for k = 1:n_lambda % n_lambda is the number of bands
temp = img(:, k); % img is the monochromatic image that should fill a diagonal line
hcube = assignData(hcube, :, k, k, temp);
end
the function assignData is defined in the Image Processing Toolbox Hyperspectral Imaging Library and works fine outside the for loop.
Whenever I try to execute the code it gives me "Unrecognized function or variable 'assignData'." in the line with this function.
Since directly indexing inside the hcube.DataCube object is not possible this function seems to be the only option to change hyperspectral data.
  1 Comment
Geoff Hayes
Geoff Hayes on 5 Nov 2020
Peter - can you show more of your code? It isn't clear why calling this function within the loop would fail whereas calling it outside the loop would succeed.

Sign in to comment.

Accepted Answer

Steve Eddins
Steve Eddins on 5 Nov 2020
One possible explanation for the observed behavior is that the variable hcube does not actually contain a hypercube object when the call to assignData happens inside your for-loop. Since we don't see the code before the for-loop, I can't really guess at why that might be. I recommend that you use the debugger and single-step through your code, making sure that the variables contain what you think they should contain at each step.
Also, does your real code include the single quotes around the colon character in the call to assignData? I don't this code will work as it is written here, without the single quotes.
  2 Comments
Steve Eddins
Steve Eddins on 6 Nov 2020
The colon character, by itself, can only be used as an array index. In this code:
hcube = assignData(hcube, :, k, k, temp);
assignData is a function, not an array. You can't pass the colon character by itself as an argument to a function.

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by