datevec back to regular time
4 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Jo Bremer Balestracci
le 9 Nov 2020
Commenté : Walter Roberson
le 9 Nov 2020
I am using datevec and performing calulations. The end result needs to be converted back to a regular time for the user. I have tried different things and I am still am getting the result I want. I did not put a date in which I normally do using the Date Picker. Can you help me?
t=datevec(state.TimeHHMMssEditField); % where state.TimeHHMMssEditField = 1:31:00
desiredTime = t(4) *3600 + t(5) * 60 + t(6);
NewTime =desiredTime % 5460
StartTime = NewTime + .5 %5460.5
Duration = (state.DurationinsecondsEditField)' % where state.DurationinsecondsEditField = 30 seconds
EndTime = StartTime + Duration %5490.5
% EndTime is in seconds. I want to convert the EndTime (5490.5) to look like 1:31:35
How do I do this?
0 commentaires
Réponse acceptée
Walter Roberson
le 9 Nov 2020
datestr(EndTime/(3600*24),'HH:MM:ss')
However, this will have leading 0 . Leading 0 is used automatically if you do not use AM indicator.
I would recommend, by the way, that you switch to using datetime and duration objects, which make the code a lot cleaner.
5 commentaires
Walter Roberson
le 9 Nov 2020
'HH:MM:ss.ff' for serial datenum work.
'HH:mm:ss.SS' for datetime() work.
Plus de réponses (1)
Steven Lord
le 9 Nov 2020
I second Walter Roberson's suggestion to skip the datevec form and to use duration.
t = '1:31:00'
du = duration(t)
newtime = du + seconds(0.5)
newtime.Format = 'hh:mm:ss.SSS' % Show fractional seconds
newt = string(newtime) % or char(newtime)
0 commentaires
Voir également
Catégories
En savoir plus sur Calendar dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!