Is there a matrix which can be alphanumeric?

I am trying to make a matrix like

    1n  -1 
    1n   2 
    1n   1 
    1n   3 

The first column is going to be concatenated string where the first alphabet is the counter of the for loop and the alphabet 'n'

For ex: for coun = 1:1:10

code will go here

end

should give output for coun = 3 as:

3n
3n
3n
3n

and then I need to put this along with a new matrix j which is

-1
2
1
3

The order of the final matrix is decided by the matrix j as it has the same number of rows as the number of rows of the matrix j.

So the final output is:

    3n  -1 
    3n   2 
    3n   1
    3n   3 

Answer 1

[Cris LaPierre]

A matrix cannot contain mixed data types. It's possible to create a string array that does what you want, but everything will have to be strings.

a = string(ones(4,1)*3)+"n";
b = [-1 2 1 3]';
j=[a string(b)]

j = 4×2 string array
    "3n"    "-1"
    "3n"    "2" 
    "3n"    "1" 
    "3n"    "3" 

If instead you want to mix data types, you could use a table.

j=table(a,b)

j = 4x2 table
     a      b 
    ____    __

    "3n"    -1
    "3n"     2
    "3n"     1
    "3n"     3