Sorting and indexing multidimensional arrays

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Shing Bo Peh
Shing Bo Peh le 12 Nov 2020
Modifié(e) : Shing Bo Peh le 12 Nov 2020
I would like to clarify if indexing is supported for multidimensional arrays.
For example, consider the code below.
According to the help page, the line B2 = A(I) a recover the sorted array.
However, from MATLAB Online R2020b the code snippet produces array full of ones as the result for B2.
A(:,:,1) = 1*ones(3);
A(:,:,2) = 2*ones(3);
A(:,:,3) = 3*ones(3);
A(:,:,4) = 4*ones(3);
[B,I] = sort(A,3,'descend');
B2 = A(I);
  2 commentaires
Stephen23
Stephen23 le 12 Nov 2020
"According to the help page, the line B2 = A(I) a recover the sorted array."
What the sort documentation actually states is "if A is a vector, then B = A(I)" (emphasis added).
Are your data in a vector? (hint: no).
Shing Bo Peh
Shing Bo Peh le 12 Nov 2020
Thanks for the explanation, indeed A is not a vector. Your comment and Walter's answer have been helpful in extending the example to 3D arrays.

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Walter Roberson
Walter Roberson le 12 Nov 2020
See https://www.mathworks.com/matlabcentral/answers/645463-help-required-for-sorting#answer_542268 -- I just happened to write up an explanation for someone of the same basic problem.
You would need to expand what I wrote there into the third dimension. You would want to change the repmat() that I show there into something more like
[ROWIDX, COLIDX] = ndgrid(1:size(A,1), 1:size(A,2));
B2 = sub2ind(size(A), ROWIDX, COLIDX, sortidx);
This is untested; you might need to use meshgrid() instead of ndgrid()
  3 commentaires
Walter Roberson
Walter Roberson le 12 Nov 2020
Thanks for the test case, Bruno!
Shing Bo Peh
Shing Bo Peh le 12 Nov 2020
Confirmed, thank you Bruno.

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Bruno Luong
Bruno Luong le 12 Nov 2020
Modifié(e) : Bruno Luong le 12 Nov 2020
[B,I] = sort(A,3,'descend');
I is ndarray same size as A and B, values is 1:size(A,3) such that for any i,j
A(i,j,I(i,j,:))
is equal to
B(i,j,:)
(Both are then sorted in descending order)

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