App Designer: Temperature Unit Converter (Error using matlab.ui.​control.Ed​itField)

Error using matlab.ui.control.EditField/set.Value (line 98)
'Value' must be a character vector or a string scalar.

I am using Matlab app designer to create a unit converter. but i have error ;(

 app.Type1 = app.FromDropDown.Value;
            if strcmp (app.Type1,'Cesius')==1
                if strcmp(app.Type2,'Cesius')==1
                    app.Tout=app.Tin;
                    app.OutputTemperatureEditField.Value=app.Tout;
                    
                elseif strcmp(app.Type2,'Fshrenheit')==1
                    app.Tout=app.Tin*(9/5)+32;
                    app.OutputTemperatureEditField.Value=app.Tout;
                elseif strcmp(app.Type2,'Kelvin')==1
                     app.Tout=app.Tin+273.15;
                    app.OutputTemperatureEditField.Value=app.Tout;
                elseif strcmp(app.Type2,'Rankine')==1
                     app.Tout=(app.Tin+273.15)*9/5;
                    app.OutputTemperatureEditField.Value=app.Tout;
                end
                
            elseif strcmp(app.Type1,'Fshrenheit')==1
                   if strcmp(app.Type2,'Cesius')==1
                    app.Tout=(app.Tin*-32)*5/9;
      (error)       app.OutputTemperatureEditField.Value=app.Tout;
                   elseif strcmp(app.Type2,'Fshrenheit')==1
                    app.Tout=app.Tin;
                    app.OutputTemperatureEditField.Value=app.Tout;
                 elseif strcmp(app.Type2,'Kelvin')==1
                     app.Tout=(app.Tin+459.67)*5/9;
                    app.OutputTemperatureEditField.Value=app.Tout;
                elseif strcmp(app.Type2,'Rankine')==1
                     app.Tout=app.Tin+459.67;
                    app.OutputTemperatureEditField.Value=app.Tout;

                   end

Answer 1

[Avratanu Biswas]

Hi,

Please try :

% Use num2str in all the cases
app.OutputTemperatureEditField.Value = num2str(app.Tout); 

Cheers

Avra