how can i change Matrix last row with loop?

Hi there, i am a begginer in Matlab and i have problem with solving the matrix.. The problem is that i dont know how to change last row in matrix with numbers
[0 0 0 -1] - matrix one
[0 0 -2 -1] - matrix two
[0 -3 -2 -1] - matrix three
[-4 - 3 -2 -1] - matrix four
And here is my code:
for n = 2:5
A22 = eye(n, n-1);
A21 = zeros(n, 1);
A = [A21, A22];
end
(this code is working, i only need to change last row)

 Réponse acceptée

Setsuna Yuuki.
Setsuna Yuuki. le 15 Nov 2020
this can work
for n = 2:6
A22 = eye(n, n-1);
A21 = zeros(n, 1);
A = [A21, A22];
end
A = A(1:5,:)

5 commentaires

Jan Vidlak
Jan Vidlak le 15 Nov 2020
Thanks for answering, but it doesnt work, i need to have 4 matrix (picture) that has last row in numbers, but that needs to be in someking loop. Code is still the same.
I now understand jaja
maybe this will work
for n = 2:5
A22 = eye(n,n-1);
A21 = zeros(n,1);
A = [A21, A22];
A(n,:)= -n:-1
matrix{n-1} = A;
end
Jan Vidlak
Jan Vidlak le 15 Nov 2020
Yes that works! Thank you so much:)
Jan Vidlak
Jan Vidlak le 15 Nov 2020
Modifié(e) : Jan Vidlak le 15 Nov 2020
hey, i have one more question if you know it, the eye function gives me this: E = eig(A) <-- inside loop
Is that correct(numbers)?
Setsuna Yuuki.
Setsuna Yuuki. le 15 Nov 2020
i don't know if the result is correct, but the eigenvalues can be complex.

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