How to construct and evaluate a boolean expression using symbols?

If I have a boolean expression that is

y = (x1bar∨x2)(x3bar∨x4bar)(x3bar∨x5)

I am currently using a simple 1 and 0 matrix to evaluate this sometimes manually and sometimes in a for a loop. However, it is difficult to do the same for larger expressions. Is there a way that I can evaluate these expressions using symbols like the ones we have poly2sym()? In other words, using and or logical operators and the values of the variables, can I find the answer of any boolean expression without using a for a loop as my expressions should less time to evaluate compared to the other part of the code.

Answer 1

[Walter Roberson]

[X1, X2, X3, X4, X5] = ndgrid([false,true]);
X1bar = ~X1;
X3bar = ~X3;
X4bar = ~X4;

X1barvX2 = X1bar | X2;
X3barvX4bar = X3bar | X4bar;
X3barvX5 = X3bar | X5;

y = (X1barvX2) & (X3barvX4bar) & (X3barvX5);

y_table = [X1(y), X2(y), X3(y), X4(y), X5(y)];
disp(y_table)

   0   0   0   0   0
   0   1   0   0   0
   1   1   0   0   0
   0   0   0   1   0
   0   1   0   1   0
   1   1   0   1   0
   0   0   0   0   1
   0   1   0   0   1
   1   1   0   0   1
   0   0   1   0   1
   0   1   1   0   1
   1   1   1   0   1
   0   0   0   1   1
   0   1   0   1   1
   1   1   0   1   1