How to find longest sequennce within a character array?

lets say Im given a random character array such as: 'aaabee' and i want to find the longest sequence of vowels. How would i go about doing this?
so far I have:
cArr = 'aaabee';
vow = ['a', 'e', 'i', 'o', 'u'];
ans = strfind(cArr, vow);
but this just returns: [ ]
anyhelp would be appreciated!

Réponses (2)

Ameer Hamza
Ameer Hamza le 16 Nov 2020
Modifié(e) : Ameer Hamza le 16 Nov 2020
You can use regexp
cArr = 'xzyhd';
vow = '([aeiou]+)';
tkns = regexp(cArr, vow, 'tokens');
if isempty(tkns)
n = 0;
else
n = max(cellfun(@numel, [tkns{:}]));
end
Result
>> n
n =
5

3 commentaires

Awesome!
That Guy
That Guy le 16 Nov 2020
Modifié(e) : That Guy le 16 Nov 2020
this works, i just need it to output zero when a string without vowels is entered such as 'xzyhd' or ' ' .
sorry im so helpless this is my first experince with coding:(
I have updated the answer. Now it will output 0 for the mentioned cases.

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Setsuna Yuuki.
Setsuna Yuuki. le 16 Nov 2020
Modifié(e) : Setsuna Yuuki. le 16 Nov 2020
cArr = 'aaabee';
vow = ['a', 'e', 'i', 'o', 'u'];
for n=1:length(vow)
a = strfind(cArr, vow(n)); %search letter by letter
repeat{n} = a; %place in "cArr"
if (a ~= NaN)
long(n) = length(a); %number of repetitions
else
long(n) = 0;
end
end
t = table(vow',long')
Table:

4 commentaires

Thanks! any hints on how to modify what you have to not be as specific? I need it to find the longest sequence of any vowels ie: 'aaeeaprii' would return a max value of 5 within long(n), right now your code returns 3 instead?
Any help?
has been interesting this problem, i changed all code because I understood bad your problem.
clear large;
cArr = 'aaeeaaapriioaeaaa';
vow = ['a', 'e', 'i', 'o', 'u'];
var = 1;
for n=1:length(vow)
a = strfind(cArr, vow(n));
if(var == 1)
var(length(var):(length(var)+length(a))-1)=a;
else
var(length(var)+1:length(var)+length(a))=a;
end
end
var = sort(var); m = 0;
cont = 1;
for n = 1:length(var)-1
if(var(n) == (var(n+1)-1) && n ~= length(var)-1)
cont = cont +1;
elseif (var(n) ~= (var(n+1)-1))
m = m+1;
large(m) = cont;
cont = 1;
elseif(n == (length(var)-1))
cont = cont+1;
m = m+1;
large(m) = cont;
end
end
[longSeq, index] = max(large);
fprintf("The longest sequence is %i and is the sequence %i \n",longSeq, index);
I think I did this in C ++ jaja xd
What's the use case for this quirky thing? Why do you need to do it? It's not your homework you're asking people to do for you, is it? What's the real world use for this?

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R2019b

Question posée :

le 16 Nov 2020

Commenté :

le 16 Nov 2020

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