Rayleigh Channel power normalization

19 vues (au cours des 30 derniers jours)
Vladislav Borchsh
Vladislav Borchsh le 16 Nov 2020
I have to use a Raleign channel as built-in function. And there some misunderstanding.
I set zero-delay and zero-gain for that channel. So, I expect the channel witouh fading, because all parameters is zero. Code here:
clear all
close all
clc
Fs = 72e6;
M = 4;
dpskMod = comm.DPSKModulator('ModulationOrder', M);
dpskDemod = comm.DPSKDemodulator('ModulationOrder', M);
numBits = 1000; % Each trial uses 10000 bits.
numTrials = 10; % Number of BER computations
PathDelays = [0]*1e-9;
PathGains = [0];
rayleighCh = comm.RayleighChannel(...
'SampleRate', Fs, ...
'PathDelays', PathDelays, ...
'AveragePathGains', PathGains, ...
'NormalizePathGains', true, ...
'MaximumDopplerShift', 0, ...
'PathGainsOutputPort', true);
nErrors = zeros(1,numTrials);
for n = 1:numTrials
tx = randi([0 M-1],numBits,1);
dpskSig = dpskMod(tx);
[fadedSig, pg] = rayleighCh(dpskSig);
end
disp(pg(1));
But, each run I have different results. For example:
-0.1019 - 0.0337i
1.4275 + 0.7458i
It's means that signal's gain will changing each run. Why?
With delay==0 and gain==0 I expect constant channel for every run.

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