for i = 1 :1: N
for j = 1 :1: N
if u(i,j) < 1-a(i,j) && N<1- (u(i,j)/(1-a(i,j)))
z= (1-a(i,j))*N
end
end
end

4 commentaires

Rik
Rik le 17 Nov 2020
This time I edited your question for you. Next time, please use the tools explained on this page to make your question more readable.
What do you mean by 'it doesn't work'?
Peter Perkins
Peter Perkins le 19 Nov 2020
Also, you don't need loops at all.
z = zeros(size(a));
i = (u < 1-a) && (N < 1 - u./(1-a))
z(i) = (1-a(i)) .* N;
Nirajan Khatri
Nirajan Khatri le 20 Nov 2020
@ Rik thank you, i have u matrix and a matrix so i was trying to use conditional loop, next time i will surely do it
Nirajan Khatri
Nirajan Khatri le 20 Nov 2020
@ Peter Perkins Sir thank you

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