Finding real roots of cubic polynomial

8 vues (au cours des 30 derniers jours)
S. R. S.
S. R. S. le 17 Nov 2020
Commenté : S. R. S. le 18 Nov 2020
I want to find the only one real roots of the equation and wrote the following code:
e = 0.3; gama = 0.8; damp = 0.0031; A = 12; M = 2*10^-4; mu = 0.05/M; St = 0.2; %parameters
Ur = 4:0.1:6;
for i = 1:size(Ur,2)
del(i) = 1/(St*Ur(i));
p(i,:)=roots([1 (-(1+2*del(i)^2-(2*damp*del(i)+(gama/mu))^2)+A*M) (-(-2*del(i)^2+(2*damp*del(i)+(gama/mu))^2-del(i)^4)-A*M*del(i)^2) (-del(i)^4)]);
r = p;
r = r(imag(r) == 0 );
end
Only one real root corresponding to each 'del(i)' is required but in some iteration, 'del(i)' leads to all three real roots of 'p'. (If all the three roots are real, max value of roots out of three would be considered)
How can I improve my code?

Réponse acceptée

Andrei Bobrov
Andrei Bobrov le 17 Nov 2020
e = 0.3;
gama = 0.8;
damp = 0.0031;
A = 12;
M = 2*10^-4;
mu = 0.05/M;
St = 0.2;
AM = A*M;
%parameters
Ur = (4:0.1:6)';
n = numel(Ur);
del = 1./(St*Ur);
del2 = del.^2;
B = 2*del2-(2*damp*del+gama/mu).^2;
X = [ones(n,1) , AM-1-B , B+del2.^2-AM*del2 ,-del2.^2];
r = zeros(n,1);
for i = 1:n
p = roots(X(i,:));
r(i) = max(p(imag(p) == 0 ));
end
  1 commentaire
S. R. S.
S. R. S. le 18 Nov 2020
Thank you so much Andrei Bobrov for your brilliant work. The code served my purpose.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Polynomials dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by