Bit wise operation of And and XOR together
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f10 = 1 + v2 + x2 + x2v2 + x2v3 + x3v2 + x2w2 + x2w3 + x3w2
these are the expressions and I want to perform xor and AND operation on this for 2^8 combination in binary
And if this not correct method then how can I write this expression such that it gives 1bit output as either 0 or 1 for 2^8 combination
function a=Share1(u2,v2,w2,x2,u3,v3,w3,x3)
a=bitxor(1,v2,x2,bitxor(bitand(x2,v2),bitand(x2,v3),bitand(x3,v2),bitand(x2,w2),bitand(x2,w3),bitand(x3,w2)));
end
But it is not working.
Please someone suggest how can I write this qudratic equation using MATLAB or where I am wrong
2 commentaires
dpb
le 21 Nov 2020
Can you explain what the expression as written means?
Mathematically it looks like a simple sum of products of three variables [v,w,x] for two conditions.
Why then write a function with four variables [u,v,w,x] where it appears they correspond to the single/product terms and the result would just be the sum (plus the constant 1) of course?
Certainly seems no reason for bitwise operations here.
Réponses (2)
Setsuna Yuuki.
le 21 Nov 2020
The binary operation is between two values logics or values of 0's and 1's. In your code some logics operation are done between three logics values.
For example:
bitxor(bitand(x2,w2),bitand(x2,w3),bitand(x3,w2)) % bitxor(l1,l2,l3)
bitxor(bitxor(bitand(x2,w2),bitand(x2,w3)),bitand(x3,w2)) % bitxor(bitxor(l1,l2),l3)
Bruno Luong
le 21 Nov 2020
Modifié(e) : Bruno Luong
le 21 Nov 2020
Z=quad(0,1,1,0,1,0,1,1)
function F10 = quad(u2,v2,w2,x2,u3,v3,w3,x3)
% note: u2 and u3 not used anywhere
F10=1+v2+x2+x2*v2+x2*v3+x3*v2+x2*w2+x2*w3+x3*w2;
F10=mod(F10,2);
end
2 commentaires
Bruno Luong
le 22 Nov 2020
"It is not giving output "
It gives 0 for me.
>> testquad
Z =
0
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