How to assemble 3D array from four vectors
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Ranny Meier
le 21 Nov 2020
Commenté : Ranny Meier
le 22 Nov 2020
We have four vectors of complex numbers.
FF = 1 x N vector, FM = 1 x N vector, MF = 1 x N vector, MM = 1 x N vector
We need a 3D array G = 2 x 2 x N array, and where each page is [FF(n) FM(n); MF(n) MM(n)]
FF = [1+2i 2+2i 3+2i 4+2i 5+2i 6+2i];
FM = [7+2i 8+2i 9+2i 10+2i 11+2i 12+2i];
MF = [13+2i 14+2i 15+2i 16+2i 17+2i 18+2i];
MM = [19+2i 20+2i 21+2i 22+2i 23+2i 24+2i];
G = [FF(1) FM(1); MF(1) MM(1)];
for n = 2:6
G(:,:,n) = [FF(n) FM(n); MF(n) MM(n)];
end
G
We tried to assemble it with a reshape function after taking noncongugate transpose.
R = reshape([FF.' MF.'; FM.' MM.'].',2,2,[])
The result is the correct shape of 3D array, and yet it seems that the elements are mixed up.
Is there a better way to assemble this 3D array, other than adding a page at a time in a loop?
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the cyclist
le 21 Nov 2020
Modifié(e) : the cyclist
le 21 Nov 2020
Here is one way:
G = reshape([FF; MF; FM; MM],2,2,6)
3 commentaires
the cyclist
le 22 Nov 2020
I postsed that first solution too fast, which is part of the reason I edited it quickly.
The first solution, which I edited away, should only have been:
H = permute(reshape([FF; FM; MF; MM],2,2,6),[2 1 3])
The other dimensions were stupidity, not magic. :-)
Then I realized that if I swapped FM and MF, then the permutation can be avoided, for a much cleaner solution.
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