I don't know why the results of index1 and index2 are different.
The variable
financial_status=[1,2,3,4,5];
index1 = find(financial_status==or(1,2));
index2 = find(financial_status>=1&financial_status<=2);

2 commentaires

dpb
dpb le 23 Nov 2020
Because
>> or(1,2)
ans =
logical
1
>>
TAEKYU EOM
TAEKYU EOM le 23 Nov 2020
I got it, thanks!

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 Réponse acceptée

dpb
dpb le 23 Nov 2020

0 votes

Because
>> or(1,2)
ans =
logical
1
>>
You're apparently looking for
>> ismember(financial_status,[1,2])
ans =
1×5 logical array
1 1 0 0 0
>>
Rarely are the actual indices returned by find needed, but can be if this is one of those cases that simply using the logical addressing array isn't sufficient.

Plus de réponses (1)

Walter Roberson
Walter Roberson le 23 Nov 2020
Modifié(e) : Walter Roberson le 23 Nov 2020

0 votes

ismember(financial_status, 1:2)
At the moment I cannot think of any computer language that expresses a set membership test in terms of an equality test. Which computer language were you inspired by?

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