ln is not working, please help me

I just want to know how to calculate

b in the equation of, x^b = y

the mathematical solution is ln y /ln x = b; if i remember my math right.

ln doesn't seem to work, can you give me a solution

Answer 1

[Azzi Abdelmalek]

One solution is

b=log10(y)/log10(x)

Example

x=50;
y=24
b=log10(y)/log10(x)

And now check

x^b

Answer 2

[Image Analyst]

Are you using log()? Because you don't want to use ln() which doesn't exist. log() is the natrual logarithm. What is the error message? Other than that, what you said should work, and in fact is just what Azzi did. log10 or log should both work. Not sure what you did wrong that Azzi did right, unless it was trying to use ln instead of log.

[Azzi Abdelmalek]

b=log(y)/log(x)  % Is also correct,

[bioter]

Yes i used the natural log for solving and it worked great, but i wonder why they have that function in mathworks, maybe it is a latest version which i didn't check.

anyway thanks everyone..

[Image Analyst]

I think log and log10 are fairly standard, at least in every programming language I've seen. I've not seen a language with ln, but I agree with you - it should be there. Of course you could define your own m-file called ln.m which is just a wrapper for the log function (calls log() internally).