if statement find criteria not doing what I want it to do

if k does not contain 1 matlab returns ' 1×0 empty double row vector ' so i dont understand why this is not working in my if statement, where I have wrote ' 1×0 empty double row vector' as 'zeros(1,0)'

if k does contain 1 it returns scalar 1

function[out]=neqchek(k)
c=find(k==1)
if c~=zeros(1,0)
    k(1)=10
    out=k
end
end

Answer 1

[David Hill]

function[out]=neqchek(k)
c=find(k==1)
if ~isempty(c)
    k(1)=10
    out=k
end
end

[Sara Ismail-Sutton]

okay many thanks, and would you be able to point our for me what is wrong with using zeros(0,1) ? :))

[the cyclist]

The reason your code doesn't work is that checking "equality" between two empty arrays does not return a simple true value. This is why your if statement doesn't behave as you expect.

Try something as simple as

[] == []

to see what I mean.

Answer 2

[madhan ravi]

neqchek = @(k) subsasgn(k, substruct('()', {k(1) == 1}), 10);
out = neqchek([1 : 2, 1])

out = 1×3

10 2 1

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