Piecewise to Heaviside problem

66 vues (au cours des 30 derniers jours)
xRah
xRah le 26 Nov 2020
Commenté : xRah le 26 Nov 2020
Hi all,
Trying to create a plot using heaviside function after being given a piecewise function. The code, I managed to get 2 different results, so I am not sure which is correct.
The piecewise function is the following:
x^2 - 1; if 0 <= x < 2
f(x) = 2x - 3; if 2 <= x < 5
sin(x); if x >= 5
My code is the following.
y = (t.^2-1).*[heaviside(t)-heaviside(t-2)]+(2.*t-3).*[heaviside(t-2)-heaviside(t-5)]+sin(t).*heaviside(t-5);
plot(t,y)
I may have made a mistake in the conversion to heaviside, and I am not so well versed in the step function, so it's a little challenging to analyze the graph to see whether or not it is correct. Any input is greatly appreciated!
  1 commentaire
xRah
xRah le 26 Nov 2020
I included the code that I assumed to be correct

Connectez-vous pour commenter.

Réponse acceptée

Ameer Hamza
Ameer Hamza le 26 Nov 2020
Yes, your code is correct. Following will work
t = 0:0.01:10;
y = (t.^2-1).*[heaviside(t)-heaviside(t-2)]+(2.*t-3).*[heaviside(t-2)-heaviside(t-5)]+sin(t).*heaviside(t-5);
plot(t,y)
However, an easier solution is to use piecewise()
syms x
f(x) = piecewise(0<=x<2, x^2-1, 2<=x<5, 2*x-3, 5<=x, sin(x));
fplot(f, [0 10])
  1 commentaire
xRah
xRah le 26 Nov 2020
It seems that using the piecewise route shows the same graph as mine. I forgot to include the values of t in the code above. Thank you Hamza for the clarification. I really do appreciate it!

Connectez-vous pour commenter.

Plus de réponses (1)

Walter Roberson
Walter Roberson le 26 Nov 2020
syms f(x) t
f(x) = piecewise(x<0, 0, 0 <= x & x < 2, x^2 - 1, 2 <= x & x < 5, 2*x - 3, 5 <= x, sin(x));
f(t)
ans = 
sympref('HeavisideAtOrigin', 1);
y = (t.^2-1).*[heaviside(t)-heaviside(t-2)]+(2.*t-3).*[heaviside(t-2)-heaviside(t-5)]+sin(t).*heaviside(t-5)
y = 
yp = rewrite(y, 'piecewise')
yp = 
fplot(f(t)-y, [-1 10])
The formulas come out the same except in a different order of cases, and the difference between the two appears to be all zero
  1 commentaire
xRah
xRah le 26 Nov 2020
Hi Walter and thank you for your input.
I am not entirely sure I follow everything you did, but how come your output graph looks different from my output?

Connectez-vous pour commenter.

Produits


Version

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by