Smoothing the plots with points

1 vue (au cours des 30 derniers jours)
Doyeon Kim
Doyeon Kim le 28 Nov 2020
Commenté : KSSV le 28 Nov 2020
x1 = [0.05, 0.101, 0.201, 0.401, 0.797, 1.597, 3.196, 6.39, 10.01];
y1 = [0.053, 0.832, 2.744, 3.737, 3.775, 3.823, 3.9, 4.039, 4.207];
x2 = [0.049, 0.097, 0.2, 0.403, 0.739, 1.596, 3.201, 6.39, 10];
y2 = [0.113, 0.797, 6.096, 7.271, 7.426, 7.603, 7.894, 8.266, 8.666];
x3 = [0.05, 0.099, 0.201, 0.402, 0.804, 1.6, 3.219, 6.38, 10];
y3 = [0.25, 1.595, 7.889, 11.403, 12.502, 12.7, 13.54, 14.672, 15.6];
How to smooth those? Also, I want to limit the x axis from 0 to 10.
  1 commentaire
KSSV
KSSV le 28 Nov 2020
Have a look on interp1

Connectez-vous pour commenter.

Réponses (1)

KSSV
KSSV le 28 Nov 2020
Try fitting a Bezier Curve: I have referred this link: https://in.mathworks.com/matlabcentral/fileexchange/33828-generalised-bezier-curve-matlab-code . Please note that code can be optimized.
x1 = [0.05, 0.101, 0.201, 0.401, 0.797, 1.597, 3.196, 6.39, 10.01];
y1 = [0.053, 0.832, 2.744, 3.737, 3.775, 3.823, 3.9, 4.039, 4.207];
% From here take from the link
p = [x1' y1'] ;
n = size(p,1) ;
n1 = n-1 ;
sigma = zeros(1,n1+1) ;
for i=0:1:n1
sigma(i+1)=factorial(n1)/(factorial(i)*factorial(n1-i)); % for calculating (x!/(y!(x-y)!)) values
end
l=[];
UB=[];
for u=0:0.002:1
for d=1:n
UB(d)=sigma(d)*((1-u)^(n-d))*(u^(d-1));
end
l=cat(1,l,UB); %catenation
end
P=l*p;
figure
hold on
plot(p(:,1),p(:,2),'b')
plot(P(:,1),P(:,2),'r')
legend("Original","BeizerCurve")
  2 commentaires
Doyeon Kim
Doyeon Kim le 28 Nov 2020
Thanks a lot!
KSSV
KSSV le 28 Nov 2020
Thanks is accepting/voting the answer.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Curve Fitting Toolbox dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by