iteration with biscetion method
Afficher commentaires plus anciens
Hello i need som help with program this code. I have the following parameters in a matrix[1566,1] R, I, Q_min, Q_max, A and d. And i want to solv the eq with the biscetion methode. i want the result to come out in a matriv?
%%%%%%%%%%%%%%%%%%%%%%%%%%Parameter %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
data=xlsread('ledning.xls');
Q_min=data(:,2);
R=data(:,5)/4; % Hydraulisk radius for fuldløbende ledning
I=data(:,4); %I=I_0 dvs. slope
A=(data(:,5)/2).^2*3.14;
M=75;
d=data(:,5);
for i=1:length(data)
Q_max(i,1)=abs(A(i,1)*M*(I(i,1)/100)^(1/2)*R(i,1)^(2/3));
end
for i=1:length(data)
p(i,1)=Q_min(i,1)/Q_max(i,1);
end
%%%%%%%%%%%%%%%%%%%%%%%%Ligning der skal løses %%%%%%%%%%%%%%%%%%%%%%%%%%%
%Ligningen løses via biscetion metoden
f=@(y) (0.46-0.5*cos(3.14*(y/d))+0.004*cos(2*3.14*(y/d)))-(p); %delfyldningsformel
format long
%%%%%%%%%%%%%%%%%%%%%%%%Betingelser til biscetion %%%%%%%%%%%%%%%%%%%%%%%%
eps_abs = 1e-5;
eps_step = 1e-5; %%%%abs og step angiver hvor tæt resultaterne skal være på hinanden
a = 0; % Initial Guess to your function such that f(a)>0.
b = 0.2; % Initial Guess to your function such that f(b)<0.
%%%%%%%%%%%%%%%%%%%%%%%%Påbegynd loop %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
while (b - a >= eps_step || ( abs( f(a) ) >= eps_abs && abs( f(b) ) >= eps_abs ) )
c = (a + b)/2;
if ( f(c) == 0 )
break;
elseif ( f(a)*f(c) < 0 )
b = c;
else
a = c;
end
end
1 commentaire
Jan
le 12 Mar 2013
What does the posted code do in opposite to your demands?
Réponses (0)
Catégories
En savoir plus sur Creating and Concatenating Matrices dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!