Comparing two array of bit

I need to understand how much similar two arrays,

I have many '1×2048' array of bits and I need to how much similar these. Is there any criteria for this?

I don't know this but I tried overlatpink criteria but looks not working...

Here

find((and(rf4,f4))~=1 )

but I can't found numbers of bits 1.

K>> find((and(rf4,f4))~=1 )

ans =
  Columns 1 through 14
           1           2           3           4           6           7           9          12          13          16          17          18          20          21
  Columns 15 through 28
          22          23          24          26          27          30          31          34          35          36          37          38          39          40
  Columns 29 through 42
          42          43          44          45          46          47          48          49          50          51          54          55          56          58
  Columns 43 through 56
          60          62 
          ...

How can I do difference measurement of two array?

Answer 1

[zübeyir ddds]

Thanks to @Walter Roberson for correct answer

nnz command solved the problem

% I need to calculate which bits false and used and operator 
a=[1 0 0 0 0 0]

a =

     1     0     0     0     0     0

>> b=a

b =

     1     0     0     0     0     0

>> nnz(and(a,b))

ans =

     1

Answer 2

[KALYAN ACHARJYA]

result=array1==array2

Considering, both are logical data type, as you mentioned '1×2048' array of bits'

Later you can use sum to see the total result, more sum value refelects more simmilar.

[zübeyir ddds]

How can I count result bits which 1 or 0

cause I have 2000 bits takes so long counting these

[Walter Roberson]

nnz(array1 == array2)

[zübeyir ddds]

thank you, thats works well