Effacer les filtres
Effacer les filtres

Storing Maximum Value & corresponding variable in iterative process.

1 vue (au cours des 30 derniers jours)
Shantanu K
Shantanu K le 21 Mar 2013
max1 = [-inf 0 0 0];
for p=1:3
for q=1:6
for z=1:100
if p+q<6;
a=2*p;
b=5*q;
k=z*z;
x=k*4+1;
k1 = a*x+b*k+1;
if k1 > 4,
max(1,z) = k1;
max(2,z) = p;
max(3,z) = q;
max(4,z) = z; end
else
end
end
end
end
Here there are total three loops used for p,q,z. I want to store value pf k1 which is more than 4 & corresponding p,q,z. i am facing problem that while loop is executed values of variable max are getting replaced in every loop. I have to gather data having k1>4 and correponding p,q,z

Réponses (1)

Jan
Jan le 21 Mar 2013
The minimal possible value of k1 is 16, when I set the minimal values for p, q, z in the formula k1 = a*x+b*k+1. Therefore you can omit the check for > 4. And all possible combinations with p+q<6 are wanted as result? This could be achieve much easier.
The indentation of your code is confusing due to the "end" which is append behinde the line.
You pre-allocate the variable max1, but in the code max is assigned, but it leads to problems frequently, when built-in functions are shadowed.
  1 commentaire
Shantanu K
Shantanu K le 21 Mar 2013
okay...max1 is mistake of mine.....then how to proceed. This is not actual problem....i have made replication to make it simple. Logic which i will get here will be implemented in main program......in that program its not so easy to tell about minimum value......so how to proceed then?

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