how to use the 'solve' function?

hello, im having problem trying to use the solve problem. it's not my first time using it but thata the first time its not working. i have this code line:
tmp = solve('x/L = (1-(h+eta)/ho) - A*log(((h+eta)/ho - A)/(1-A))','eta');
all the parameters are known except 'eta', still it does not provide a solution.
how can i fix it? any sugestions? thank you

Réponses (6)

Carlos
Carlos le 27 Mar 2013

1 vote

Using arbitrary values for x, h, h0, A and L
>> syms eta;
>> x=1;h=1;ho=1;A=0.1;L=1;
>> f=x/L -(1-(h+eta)/ho) - A*log(((h+eta)/ho - A)/(1-A));
>> eval(solve(f,eta))
ans =
-1.1068 - 0.2302i

1 commentaire

Jaimie Ritchie
Jaimie Ritchie le 22 Nov 2023
This was incredibly helpful to me in learning to use the solve function. I was able to plug in my equation and get a result. Thank you!

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Carlos
Carlos le 27 Mar 2013

0 votes

Doing
>> tmp = solve('x/L = (1-(h+eta)/ho) - A*log(((h+eta)/ho - A)/(1-A))','eta')% no semicolon here
tmp =
A*ho - h + (ho - A*ho)/(exp(wrightOmega(log((ho - A*ho)/(A*ho)) - (x/L + h/ho - (h - A*ho)/ho - 1)/A))*exp((x/L + h/ho - (h - A*ho)/ho - 1)/A))
It does give a solution.
Dany
Dany le 27 Mar 2013

0 votes

thats what im getting too. but i supose to have a numeric answer. i cant use the 'eval' function because it does not recognize 'wrightOmega'.
thats the problem.
Dany
Dany le 27 Mar 2013

0 votes

ok, thank you Carlos.
i'll give it a try

1 commentaire

Carlos
Carlos le 27 Mar 2013
Modifié(e) : Carlos le 27 Mar 2013
I think it should work, just remember to change the values of x,h... Please comment if something does not work by trying my approach to the problem.

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Dany
Dany le 27 Mar 2013

0 votes

sorry Carlos, it still does not work.
i try it with this values (real ones): h = 1.3721, ho = 500, L = 20000, x = 54.8828, A = -1.6452e-008.
and i still get the 'wrightOmega' and no answer .....
Dany
Dany le 27 Mar 2013

0 votes

ok it works..... thank you

1 commentaire

Carlos
Carlos le 27 Mar 2013
You are welcome, please mark my answer so people know the answer is correct and can use my answer for their problems.

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Question posée :

le 27 Mar 2013

Commenté :

le 22 Nov 2023

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