How to move elements of vector

How would I be able to find certain elements of a vector and move them?

For example, fidning the zeros in a vector and moving them to the right,

so [6 0 9 4; 0 4 0 6; 7 0 8 6; 4 5 0 9]

becomes [6 9 4 0; 4 6 0 0; 7 8 6 0; 4 5 9 0]

I have tried

vec = [vec(vec~=0) vec(vec==0)] but was unsuccessful.

Any help is appreciated thank you!

[Fangjun Jiang]

Because there are diffferent number of zeros in each row, I think you need to go through a for-loop, do it row by row should be relatively easy.

Answer 1

[James Tursa]

Could use a loop on the rows with logical indexing. E.g.,

vec = whatever
z = (vec == 0);
for r=1:size(vec,1)
    vec(r,:) = [vec(r,~z(r,:)) vec(r,z(r,:))];
end

[julie st cyr]

Just what I was looking for thank you so much!

Answer 2

[Ameer Hamza]

Try this

M = [6 0 9 4; 0 4 0 6; 7 0 8 6; 4 5 0 9];

[~, cols] = sort(M==0,2);
rows = repmat((1:size(M,1)).', 1, size(M,2));
M_new = M(sub2ind(size(M), rows, cols));

Result

>> M_new
M_new =
     6     9     4     0
     4     6     0     0
     7     8     6     0
     4     5     9     0

Answer 3

[jessupj]

i can't think of how you might do this without a loop and maintain the matrix form. but your approach will work row-by-row

for k=1:size(vec,2);
    vec(k,:) = [vec(k, vec(k,:)~=0) vec(k, vec(k,:)==0) ];
end