I'm getting the error "Array indices must be positive integers or logical values." and it seems like I structures the for loop to handle the equations. Can anyone help me with this?
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Matthew Williams
le 13 Déc 2020
Réponse apportée : Gouri Chennuru
le 16 Déc 2020
ds=zeros(length(y),1);
dAs=zeros(length(y),1);
Ac=zeros(length(y),1);
for j=1:N
t1=(t(y(j))+t(y(j+1/2)))/2; %average thickness of CV on side closer to y=0
t2=(t(y(j-1/2))+t(y(j)))/2; %avgerage thickness of CV on side closer to y=L
ds(j)=sqrt((t(y(j+1))-t(t(j-1))).^2+(2*dy).^2)/2; %using central difference
dAs(j)= (w+((t1+t2)/L))*ds(j)*dx; %surface area
Ac(j)=(t(y(j)))*dx; %Cross sectional area
end
3 commentaires
Walter Roberson
le 13 Déc 2020
You cannot index at half-integers . You can index a value and divide the result by 2, though.
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Gouri Chennuru
le 16 Déc 2020
Hi Matthew,
As per my understanding, you are trying to extract the variable "y" with indices (j+1/2) and (j-1/2), from the following lines.
t1=(t(y(j))+t(y(j+1/2)))/2;
t2=(t(y(j-1/2))+t(y(j)))/2;
You cannot point arrays to a particular decimal index.As a workaround make sure that array Index is always a positive integer or a logical value.
Regards,
Gouri Chennuru
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