How to input a string of integers and hex values together as an input. [9,0xa,0xb]
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1.) I am trying to make this string [0,1,2,3,4,5,6,7,8,9,0xA,0xB] as an input the convert to decimal value and/or binary?
Is this possible?
0xA = 10
0xB = 11
they are both Hex inputs.
2.) Then I am trying to convert this string of values to Chars.
Here is what I am got so are with the error:
Array = [0,1,2,3,4,5,6,7,8,9,0xa,0xb]
Array = dec2hex(Array)
Array = convertStringsToChars(Array)
Here is the output showing on the command window.
>> untitled2
Error: File: untitled2.m Line: 12 Column: 32
Invalid expression. Check for missing multiplication operator, missing or unbalanced delimiters, or other syntax
error. To construct matrices, use brackets instead of parentheses.
3 commentaires
James Tursa
le 15 Déc 2020
Modifié(e) : James Tursa
le 15 Déc 2020
What I mean is that for this specific example you gave:
Array = [0,1,2,3,4,5,6,7,8,9,0xa,0xb]
which contains 12 double values, what exactly is your desired output? I don't mean a description ... I mean the exact output you want for that exact input.
Réponses (2)
Matt Gaidica
le 15 Déc 2020
reshape(dec2bin(Array),1,[])
7 commentaires
Matt Gaidica
le 15 Déc 2020
I'm not sure what's going on. The attached file results with:
Array =
1×12 uint8 row vector
0 1 2 3 4 5 6 7 8 9 10 11
ans =
'000000001111000011110000001100110011010101010101'
ans =
'000000000000000000000000000000000000000000000000000000001111000011110000001100110011010101010101'
I'm running MATLAB 2020b. My hex numbers do not have the red warning underneath them. Perhaps try: 0xA, 0xB?
Steven Lord
le 15 Déc 2020
Array = [0,1,2,3,4,5,6,7,8,9,0xa,0xb]
From the fact that Code Analyzer flags this as an error, are you certain you're using release R2020a? Can you post the output of this command in your installation of MATLAB to confirm that?
version
3 commentaires
Steven Lord
le 15 Déc 2020
Because you're using the release before the capability to enter hex literals was introduced, you will not be able to type 0xa and have MATLAB turn that into uint8(10). As Rik suggested see Jan's answer, or if you're going to want to use this new functionality look at the Release Notes and consider if upgrading to a newer release is an option.
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