What is wrong with my code?

3 vues (au cours des 30 derniers jours)
Amit
Amit le 2 Avr 2013
I am currently doing a school project where i have to plot the trajectory of a projectile launched from the ground with initial speed V0, and angle theta above the horizontal. The projectile has to hit a target distance D=10000m away once it has reached the ground. I have used an initial guess of theta=pi/30 as the angle, so that the projectile does not reach D. The program should then automatically pick a new value of theta. I am doing this by increasing theta from pi/30 in steps dtheta=0.1 until the target is overshot. However, after plotting, I keep getting a wrong and wild graph. Here is my code:
%contants
D=10000;
u=600;
m=50;
g=9.81;
%initial conditions
theta=pi/30;
x=0;
i=0;
t=0;
y=0;
dtheta=0.1;
dt=0.1;
while x(i+1)<D
for i=1:1000
xdot(i)=u*cos(theta);
ydot(i)=u*sin(theta);
v(i)=sqrt(xdot(i).^2+ydot(i).^2);
x(i+1)=(t.*xdot(i));
y(i+1)=(t.*ydot(i))-(0.5*g*(t.^2));
xdbldot(i)=0;
ydbldot(i)=-g;
vel_x(i+1)=xdot(i)+(t.*xdbldot(i));
vel_y(i+1)=ydot(i)+(t.*ydbldot(i));
t=t+dt;
if y(i+1)<0
break
end
end
if x(i+1)<D
theta=theta+dtheta;
if x(i+1)>D
break
end
end
end
plot(x,y),grid
xlabel('Distance/[m]')
ylabel('Height/[m]')
  1 commentaire
Amit
Amit le 2 Avr 2013
Basically, what I am trying to do is increase the angle, theta, in steps dtheta, until the target, D=10000m, is overshot. I have tried doing this by implementing an if loop, as can be seen above.
However, it just doesn't work, any help will be greatly appreciated.

Connectez-vous pour commenter.

Réponse acceptée

the cyclist
the cyclist le 2 Avr 2013
I think maybe you want this:
x(i+1)=x(i) + (t.*xdot(i));
y(i+1)=y(i) + (t.*ydot(i))-(0.5*g*(t.^2));
when you update x and y.
  9 commentaires
Amit
Amit le 13 Avr 2013
If you have some time, could you please help with one final thing? Now, I have incorporated the part where a parachute is deployed at t_pchute=15 seconds. My initial guess for theta is now pi/12 and dtheta=theta/100. At the moment, the trajectory falls short of the D=10000m target. Once again, I would like to know how I can increase the angle theta iteratively in steps dtheta?
I was told to use theta(i+1)=atan(vy(i)/vx(i)) but I have no idea why.
%Constants
D=10000;%m
u=600;%m/s
m=50;%kg
t_pchute=15;%s
g=9.81;%m/s^2
a_proj=0.01;%m^2
a_pchute=0.05;%m^2
C_proj=0.4;
C_pchute=1.2;
p0=1.207;%kg/m^3
theta=pi/12;
dtheta=theta/100;
%initial conditions
x=0;
i=0;
t=0;
y=0;
dt=0.1;
p=p0;
vx=u*cos(theta);
vy=u*sin(theta);
v=sqrt(vx.^2+vy.^2);
for i=1:1000
Fa(i+1)=0.5*p(i)*C_proj*a_proj*v(i);
Fp(i+1)=0.5*p(i)*C_pchute*a_pchute*v(i);
if t<t_pchute
ax(i+1)=-((Fa(i)*cos(theta(i)))/m)*vx(i);
ay(i+1)=-g-(((Fa(i)*sin(theta(i)))/m)*vy(i));
else
ax(i+1)=-((Fp(i)*cos(theta(i)))/m)*vx(i);
ay(i+1)=-g-(((Fp(i)*sin(theta(i)))/m)*vy(i));
end
vx(i+1)=vx(i)+(dt.*ax(i));
vy(i+1)=vy(i)+(dt.*ay(i));
v(i+1)=sqrt(vx(i).^2+vy(i).^2);
x(i+1)=x(i)+(dt.*vx(i));
y(i+1)=y(i)+(dt.*vy(i));
p(i+1)=p0*(1-2.333e-5*y(i+1)).^5;
theta(i+1)=atan(vy(i)/vx(i));
t=t+dt;
if y(i+1)<0
break
end
end
plot(x,y),grid
xlabel('Distance/[m]')
ylabel('Height/[m]')
title('Projectile Trajectory')
Amit
Amit le 13 Avr 2013
I believe that, at the moment, theta changes at each iteration. I would like it to increase by dtheta from the beginning, where x=0 and plot the graph until x(end) and y=0. Whilst x(end) is less than D (10000 metres), theta should increase by dtheta, and the graph should be re-plotted from the the start where x=0. When x(end) reaches D, theta should stop increasing. Not sure how I do this though? Thanks

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Mathematics dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by