bandwith of high pass filter

num = [-c1/c4, 0, 0];
den = [1, (c1+c4+c3)/(R5*c4*c3), 1/(R5*R2*c4*c3)];
H_HP = tf(num, den);

wcut=sqrt(1/(R5*R2*c4*c3));
Q=wcut/((c1+c4+c3)/(R5*c4*c3));

figure;
bode(H_HP)
slope=H_HP/2

Answer 1

[Raunak Gupta]

Hi,

I am not sure if the code is to find the bandwidth, but in my opinion bandwidth must not exist for a high pass filter since it is able to pass all the frequency components above a certain cutoff frequency. So, a cutoff frequency make sense but bandwidth for a high pass filter is not something which can be find.