code from digital signal processing using matlab, 3rd edition
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M = 25;
alpha = (M-1)/2;
n = 0:M-1;
hd = (2/pi)*((sin((pi/2)*(n-alpha)).^2)./(n-alpha));
hd(alpha+1)=0;
w_han = '(hann(M))';
h = hd .* w_han.';
[Hr,w,c,L] = Hr_Type3(h);
subplot(2,2,1); stem(n,hd); title('Ideal Impulse Response')
axis([-1 M -1.2 1.2]); xlabel('n'); ylabel('hd(n)')
subplot(2,2,2);
stem(n,w_han);
title('Hann Window');
axis([-1 M 0 1.2]); xlabel ' n '); ylabel('w(n)')
subplot(2,2,3); stem(n,h);title('Actual Impulse Response')
axis([-1 M -1.2 1.2]); xlabel('n'); ylabel('h(n)')
w = w'; Hr = Hr';
w = [-fliplr(w), w(2:501)]; Hr = [-fliplr(Hr), Hr(2:501)];
subplot(2,2,4);plot(w/pi,Hr); title('Amplitude Response');grid;
xlabel('frequency in pi units'); ylabel('Hr'); axis([-1 1 -1.1 1.1]);
2 commentaires
Image Analyst
le 27 Déc 2020
Modifié(e) : Image Analyst
le 27 Déc 2020
What about it? Do you have a question about it? Doesn't run for me because you forgot to include Hr_Type3(). Please supply the function Hr_Type3() if you want us to try the code.
muhammad nur adri nawi
le 27 Déc 2020
Réponse acceptée
Plus de réponses (0)
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